Question 1040824
What method do you want to use?


{{{(-16)^2-4*4*15=256-240=16=4^2}}}


The quadratic member <s>is</s> <i>seems</i> factorable.  Look for the combinations of binomials which work(?).  Further, if you do not want to test several factorizations, you now have the discriminant and can easily plug what you need into the general solution formula.



{{{x=(16+- 4)/(2*4)}}}