Question 1040773
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If the graph does not traverse any portion of QIV, then both the slope and the y-intercept must be positive.  Putting the equation into slope intercept form:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  y\ =\ \frac{-a}{b}x\ +\ \frac{5}{b}]


So


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  \frac{5}{b}\ >\ 0]


and


*[tex \LARGE \ \ \ \ \ \ \ \ \ \  \frac{-a}{b}\ >\ 0]



John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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