Question 1040761
(2x-5)(3x+2)-(x^2-3x-8)=?
Foil out the first
6x^2+4x-15x-10
that is
6x^2-11x-10
-(x^2-3x-8)
distribute the minus sign.
6x^2-11x-10
-x^2+3x+8
5x^2-8x-2 ANSWER