Question 1040772
{{{(a+2b)/2=26}}}
{{{a+2b=52}}}
.
.
{{{(b+2c)/2=41}}}
{{{b+2c=82}}}
.
.
{{{(c+2a)/2=23}}}
{{{c+2a=46}}}
Adding them all together,
{{{a+2b+b+2c+c+2a=52+82+46}}}
{{{3a+3b+3c=180}}}
{{{a+b+c=60}}}
So then,
{{{(a+b+c)/3=60/3}}}
{{{(a+b+c)/3=highlight(20)}}}