Question 1040744
 from box containing 4 black balls and 2 green balls are drawn in succession .Each ball is place back in the box before the next draw is made . what is the possible outcome of 4 black and 2 green balls ?
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The probabilities of each draw are the same because you replace 
the ball after drawing it.
P(4 black and 2 green) = (4/6)^4*(2/6)^2 = (2/3)^4*(1/3)^2 = 0.0219
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Cheers,
Stan H.
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