Question 1040749
(i)  {{{graph( 300, 200, -pi, pi, -4, 4, 3sin(x), (6/pi)x)}}}


(ii) k will just be the slope of the line passing through the origin.

Since the maximum is 3 over the interval, the slope is {{{m = (3-0)/(pi/2-0) = 6/pi}}}. Thus {{{k = 6/pi}}}. (The coordinates of the maximum are ({{{pi/2}}},3).)


(iii) The other point of intersection would be  ({{{-pi/2}}},-3), due to symmetry wrt the origin.