Question 90317
{{{x^2-y^2 = 4}}}
Write your equation in the standard form for a hyperbola with the center at (0, 0) and the vertices on the x-axis.: {{{(x^2/a^2)-(y^2/b^2) = 1}}}
{{{x^2-y^2 = 4}}} Divide both sides by 4.
{{{(x^2/4)-y^2/4) = 1}}} Rewrite as:
{{{(x^2/2^2)-(y^2/2^2) = 1}}}
Let's see what the graph looks like!
{{{graph(600,400,-10,10,-10,10,sqrt(x^2-4),-sqrt(x^2-4),x,-x)}}}
The center is at (0, 0) and the assymptotes are:
{{{y = (a/b)x}}} and {{{y = -(a/b)x}}} or, in this case:
{{{y = x}}} and {{{y = -x}}}