Question 1040715
The slope for the given line is  {{{(1/5)}}} and any line in the plane perpendicular to it will have  slope  {{{-5}}}.  Perpendicular lines in a plane have slopes which are negative reciprocals.



Now the question is, what is the equation for a line passing through point (4,-8) and with slope  {{{-5}}}?


Using the point-slope form of equation,  {{{highlight(y-(-8)=-5(x-4))}}}.
Simplify this and solve for y in terms of x.
{{{y+8=-5x+20}}}
{{{y=-5x+20-8}}}
{{{highlight(highlight(y=-5x+12))}}}-------the same line but now in slope-intercept form.



{{{graph(300,300,-6,6,-6,6,x/5+3,-5x+12)}}}