Question 1040645
x, x+2, x+4 are integers
2x(x+2)-16=(x+2)(x+4).  Twice the product of the first minus 16 will be the product of the second.
2x^2+4x=x^2+6x+8, expanding.
x^2-2x-24=0, collecting terms
(x-6)(x+4)=0
x=6,-4 are possibilities
6,8,10 and -4,-2,0
2(6*8)=96
8*10=80, and add 16 get 96.
So 6,8,10 are the integers
check -4,-2,0
2(-4*-2)=16
That is 16 more than the product of -2*0
so -4,-2, and 0 are also possible.