Question 1040645
Let n be the first even integer. Then:
2(n)(n+2)-16=(n+2)(n+4)
2n²+4n-16=n²+6n+8
n²-2n-24=0
(n-6)(n+4)=0
n=6,-4
The even integers are 6,8, and 10. &#9786;&#9786;&#9786;&#9786;