Question 1040629
Find the value of b when the arithmetic mean of b+2 and 4b+5 is 3b+2
<pre>
The 'arithmetic mean' is just the 'ordinary average'.

So we add b+2 and 4b+5, divide by 2, and set it equal to 3b+2:

{{{((b+2)+(4b+5))/2}}}{{{""=""}}}{{{3b+2}}}

Multiply both sides by 2 to clear the fraction:

{{{(b+2)+(4b+5)}}}{{{""=""}}}{{{2(3b+2)}}}

Can you simplify that and solve for b?

If not, tell me in the thank-you note form below and I'll get
back to you by email.

Edwin</pre>