Question 1040589
let p = profit
let c = cost
let s = selling price
let m = markup price.


selling price is equal to 20% off of the markup price.
this means that s = m - .20 * m which becomes s = m * (1-.2) which becomes s = m*.80 which becomes s = .80 * m


so far you have s = .80 * m


you are given that p = 100.


so far you have:


p = 100
s = .80 * m


you are given that profit = 20% of cost.
this means that p = .20 * c
since p = 100, this means that 100 = .20 * c
divide both sides of this equation by .20 and solve for c to get c = 500.


so far you have:


p = 100
s = .80 * m
c = 500


since selling price is equal to cost plus profit, you get s = 500 + 100 = 600.


in the equation of s = .80 * m, replace s with 600 to get 600 = .80 * m.
divide both sides of this equation by .80 and solve for m to get m = 600 / .8 = 750


your markup price is 750.
you take 20% off of this to get a selling price of 600.
your profit is 100 which means your cost has to be 500.
a profit of 100 is equal to 20% of 500.


all requirements of the problem have been satisfied.


your solution is that the markup price is 750.