Question 1040535
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The perimeter of rectangle is 300 yards. What are the dimensions of the rectangle 
if the length is 70 yards more than the width. 
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L + W = 150    (1)    ( 150 = {{{300/2}}} !)
L - W =  70    (2)

Add equations (1) and (2). You will get

2L = 150 + 70 = 220  --->  L = {{{220/2}}} = 110.

From this point find W on your own.
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