Question 1040525
This problem requires the application of the  binomial probability distribution
:
recheck the probabilities you have listed, they do not match with the values of n
:
there are 7 values of n but only 6 probabilities but the 0.23 probability is suspect
:
you need to sum the probabilities and calculate the mean and standard deviation
:
standard error(SE) = sample standard deviation / square root(30)
:
test statistic = (probability from list - sample mean) / SE
you will have 6 or 7 test statistics
:
consult z-tables for the p-value corresponding to each test statistic
:
for the second part, using a binomial calculator
P ( X = 20 ) = 0.0656374
:
the probability in the choices is 0.069
: