Question 1040516
 {{{y = x^3 -10x^2 + 6}}} ==> y' = {{{3x^2 - 20x}}} ==> y" = 6x - 20.

Setting y' = 0 gives x = 0, 20/3.

At x = 0, y" = -20 < 0, ==> local maximum by the 2nd derivative test. (Not global, since {{{lim(x->infinity,y) = infinity}}}.)

At x = 20/3, y" = 20 > 0, ==> local minimum by the 2nd derivative test. (Not global, since {{{lim(x->-infinity, y) = -infinity}}}.)