<PRE><B>Question 90209</B>
a. P(2 kings 2 queens and 1 jack) = [4C2*4C2*4C1]/52C5 
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b. P(3 aces 1 king and 1 queen) = [4C3*4C1*4C1]/52C5
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c. P(1ace 1 king 1 queen and 1 jack) = [4C1*4C1*4C1*4C1]/52C4
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d. P(2diamonds and 3 hearts) = [13C2*13C3]/52C5
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Cheers,
Stan H.</PRE>