Question 1040354
the equation is y = x^3 + 1.


if this equation is symmetric about the origin, then (x,y) = (-x,-y)


if this equation is symmetric about the x-axis then (x,y) = (x,-y)


if this equation is symmetric about the y-axis then (x,y) = (-x,y)


when x = 3, y = 28
when x = -3, y = -26


if this was symmetric about the origin, then when x = -3, y would have been equal to -28 and it isn't because it is equal to -26.


if this was symmetric about the x-axis, then when x = 3, y would have been equal to plus or minus 28 and it isn't because it is equal to 28 only.


if this was symmetric about the y-axis, then when x = -3, y would have been equal to 28 and it isn't because it is equal to -26.


therefore there is no symmetry at all in this equation.