Question 1040483
all you need to do is multiply the factors together.
you would use the distributive law of multiplication.
that law says:


a * (b + c) = 
(a*b) + (a*c)


that law also says:


(a + b) * (c + d) = 
(a * (c + d)) + (b * (c + d)) = 
(a*c) + (a*d) + (b*c) + (b*d).


in other words, every term in the multiplier needs to multiply every term in the multiplicand exactly one time.


this works for any number of terms.


a more complex example would be:


(a + b + c) * (d + e + f) = 
(a * (d + e + f)) + (b * (d + e + f)) + (c * (d + e + f)) =
(a*d) + (a*e) + (a*f) + (b*d) + (b*e) + (b*f) + (c*d) + (c*e) + (c*f)


in your problem:


start with (y+2) * (y-8)
this becomes (y*(y-8)) + (2*(y-8))
which becomes (y*y) - (y*8) + (2*y) - (2*8)
simplify this to get y^2 - 8y + 2y - 16
combine like terms to get y^2 - 6y - 16


i believe that is one of your selections.