Question 90212
My problem says to graph each quadratic equation and state the vertex and intercepts. The equation is y=x^2+4x. I have to have at least 4 intercepts.  
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y=x^2+4x
Put in vertex form by completing the square on the x-terms:
y = x^2+4x+(4/2)^2 - (4/2)^2
y = x^2+4x+4 - 4
y = (x+2)^2 -4
y+4 = (x+2)^2
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Vertex at (-2,-4)
y-intercept (0,0)
x-intercepts:
 x^2+4x=0
x(x+4)=0
x=0 or x=-4
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{{{graph(400,300,-10,10,-10,10,x^2+4x)}}}
Cheers,
Stan H.