Question 1040420
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1. Solve for x. x^(2)10^(x) − 6x10^(x) = 2710^(x) 
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{{{x^2*10^x - 6x*10^x}}} = {{{27*10^x}}}     (notice I made changes in the right side !)

Cancel {{{10^x}}} in both sides. You will get

{{{x^2 -6x}}} = {{{27}}},   or

{{{x^2 -6x - 27}}} = {{{0}}}.

Factor:

(x+3)*(x-9) = 0.

The roots are x = -3 and x = 9.
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