Question 1040376

I need a two digit number which after reversing I should get a two digit  number which will be twice the previous number.
Which is the number?
<pre>Let tens and units digits be T, and U, respectively
Then number is: 10T + U, and when reversed is: 10U + T
We then get: 10U + T = 2(10T + U)
10U + T = 20T + 2U 
20T - T = 10U - 2U
19T = 8U
T, or tens digit = {{{8U/19}}}
There's no digit, from 1 - 9, that when multiplied by 8, results in a double-digit number that is a MULTIPLE of 19.
Therefore, there is: {{{highlight_green(matrix(1,2, NO, SOLUTION))}}}