<PRE><B>Question 90210</B>
the first question has 3 possible answers a, b, and c the second question has 4 possible answers a b c and d the 3rd question has 5 possible answers a b c d and e.  A student completely does not understand any question and just randomly picks an answer for each question.  

A) how many possible choices can he answer with?: 3*4*5= 60
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B) Find the probability that the student answers all 3 questions correctly
Prob(3 correct) (1/3)(1/4)(1/5) = 1/60
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C) Find the probability that the studnet answers correctly 1 question and gets the other two questions incorrect.
P(RWW or WRW or WWR) = 1/3 + 1/4 + 1/5 = 12/60 = 1/5
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Cheers,
Stan H.</PRE>