Question 1040369
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I need to solve the square root of 19-3x = x - 3 
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{{{sqrt(19-3x)}}} = {{{x-3}}}.

Square both sides:

19 - 3x = {{{(x-3)^2}}},

19-3x = {{{x^2 - 6x + 9}}},

{{{x^2 - 3x - 10}}} = {{{0}}}.

Factor

(x+2)*(x-5) = 0.

The roots are x = -2 and x = 5.

Check each of the two roots for the original equation.
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