Question 1040355
Write a slope-intercept equation for a line parallel to the line x – 5y = 9 which passes through the point (10, –3). 
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5y = x-9
y = (1/5)x - (9/5)
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slope = 1/5
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Answer Form:: y = mx + b
Solve for "b" using y = -3, x = 10, m = 1/5
-3 = (1/5)10 + b
b = -5
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Equation:
y = (1/5)x - 5
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Cheers,
Stan H.
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