Question 1040362
.Find the slope of the tangent line to the graph of f(x) = x^4 –3x at the point where the abscissa is -1.
f'(x) = 4x^3-3
f'(-1) = 4(-1)^3-3 = -7
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2. Find the slope of the line passing through the following pairs of points	
a)	(-5, 7) and (1, -5):: m = (-5-7)/(1--5) = -12/6 = -2
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b)	(4, 3) and (-8, -3):: m = (-3-3)/(-8-4) = -6/-12 = 1/2
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c)	(-1, -2) and (6, -2):: m = (-2--2)/(6--1) = 0/7 = 0
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Cheers,
Stan H.
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