Question 1040342
{{{system(f(x)=x^2+3,x<0)}}}
Domain is negative real numbers.
Range is real numbers greater than 3.



INVERSE WANTED.
Domain is real numbers greater than 3.
Range is negative real numbers.


FIND THIS INVERSE.
{{{y^2+3=x}}}
{{{y^2=x-3}}}
{{{y=-sqrt(x-3)}}}
y here is now {{{f^-1(x)}}}.
-
{{{highlight(f^(-1)(x)=-sqrt(x-3))}}}