Question 1040317
The quadratic equation has a format of ax^2+bx+c = 0

For the equation of 25x^2-9y^2+50x+250=0 to look like ax^2+bx+c = 0 is to consider -9y^2 as a constant just like 250 which is a constant. If we add these two constants we get 250-9y^2 for the simplicity we can look at 250-9y^2 as another constant like C. Then in this case we can rewrite the equation
25x^2-9y^2+50x+250 = 25x^2+50x +c 
Now we use quadratic equation to solve this. x= [-50+and - sqrt(-50)^2 -4(25)(c)]/2(25)


x = [-50+&-sqrt2500-4(25)(250-9y^2)]/50 We can multiply this a little more. However, we won't be able to have any number for x unless we know what y is.