Question 1040195
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1. What must be the value of k so that 5k-3, k+2, and 3k-11 will form an arithmetic sequence? 
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if  5k-3, k+2, and 3k-11 will form an arithmetic sequence, then

the differece (3-rd - 2-nd) = (2-nd - 1-st),  or

(3k-11) - (k+2) = (k+2) - (5k-3).

To find the value of "k", simplify and solve this equation:

3k - 11 - k - 2 = k+2 - 5k +3,  --->

2k - 13 = -4k +5,  --->  

2k + 6k = 5 + 13,

6k = 18  --->  k = {{{18/6}}} = 3.
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