Question 90248
Determine the vertex of y=x^2-8x+22.

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Complete the square on the x-terms and keep the equation balanced:
y = x^2-8x+(8/2)^2 +22 - (8/2)^2
y = (x-4)^2 + 88/4 - 64/4
y = (x-4)^ + 6
y-6 = (x-4)^2
Vertex at x=4,y=6

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{{{graph(400,300,-10,10,-10,10,x^2-8x+22)}}}
Cheers,
Stan H.