Question 1040254
Let's assume January as the first month of the year

Therefore for January t = 1
In this case The temperature for January is 
T = 50+sin (Pi/6*1) = 50 + sin (3.14/6) = 50 + sin (.52) (we know that pi = 3.14)

T = 50 + Sin .52 using calculator we have to find the sin .52 

Sin .52 = .5

Therefore T for January = 50 + 25*.5 = 50 + 12.25 = 62.25 This is our temperature for January. 
We can calculate the temperature for February by repeating this process. In case of February t = 2. Now we have to find 
T = 50+sin (Pi/6*2) When we solve this problem we will get a temperature that is less than January's temperature. Remember January's temperature is 62.25
After calculating the temperature for all 12 months we have to look at the highest number and the lowest number to see which one is the max and which one is the min. To calculate the average, we have to add all 12 numbers together and then divide it by 12.