Question 90247
Equation of a circle

{{{(x-h)^2+(y-k)^2=r^2}}} where (h,k) is the center and r is the radius




{{{(x-3)^2+(y--2)^2=4^2}}} Plug in the given info


{{{(x-3)^2+(y+2)^2=4^2}}} Simplify


{{{(x-3)^2+(y+2)^2=16}}} Square 4 to get 16