Question 1040224
(-a/9) - (b/3) + 4 = 0
-a -3b + 36 = 0
a ÷ 3b - 36 = 0
:
-16a + 4b + 4 = 0
:
We have two equations in 2 unknowns
:
a +3b - 36 = 0
16a - 4b - 4 = 0
:
Solve first equation for a
:
a = -3b  + 36
:
Substitute for a in second equation
:
16(-3b+36) -4b -4 = 0
:
-48b +576 -4b -4 = 0
-52b = -572
b = 11
a +33 -36 = 0
a = 3
:
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a = 3
b = 11
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