Question 1040210
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1. Find the equation of the circle circumscribe the triangle determined by the line y=0, 2x+3y-15=0 and x-y=0 
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<pre>
The vertices of the triangle are (0,0), (7.5,0) and (3, 3).
The center of the circumscribed circle lies in the straight line x = {{{7.5/2}}} = 3.75.
The center is the intersection of the lines y-1.5 = -(x - 1.5) and x = 3.75.
(These lines are orthogonal bisectors of the two sides).
Hence, the center is (3.75,-0.75).


Now you find the radius.
</pre>

<TABLE> 
  <TR>
  <TD> 

{{{graph( 330, 330, -5.5, 10.5, -5.5, 10.5,
          0, (15-2x)/3, x
)}}}


<B>Figure</B>. 

  </TD>
  </TR>
</TABLE>