Question 1040100
y = -x*2/8 + 11x/8 + 3/2

Find the equation of the axis of symmetry, explaining your method. Use this information to find the coordinates of the vertex, giving your answers to one decimal place.
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y = -x^2/8 + 11x/8 + 3/2 ---- Use ^ (Shift 6) for exponents.
* --> multiply
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f(x) = -x^2/8 + 11x/8 + 3/2
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AOS is x = -b/2a = (-11/8)/(-1/4)
x = 11/2
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Vertex is (11/2,f(11/2))
f(11/2) = -121/32 + 121/16 + 3/2 = 169/32
Vertex (11/2,169/32)