Question 1040042
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The unequal side of an isosceles triangle is 6 cm & its perimeter is 24 cm.find it area
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The equal sides length is {{{(24-6)/2}}} = {{{18/2}}} = 9 cm.

Then the altitude drawn to the base (which is "unequal side") is

{{{sqrt(9^2 - (6/2)^2)}}} = {{{sqrt(81-9)}}} = {{{sqrt(72)}}} = {{{6*sqrt(2)}}} cm.

Finally, the area is {{{(1/2)*6*6*sqrt(2))}}} = {{{18*sqrt(2)}}} {{{cm^2}}}.
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