Question 1040036
n and q for NICKELS and QUARTERS


{{{system(0.05n+0.25q=11.9,n+q=62)}}}
Very simple typical linear system application exercise
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Simplify the money count equation first.
{{{100(0.05n+0.25q)=100*11.90}}}
{{{5n+25q=1190}}}

{{{(1/5)(5n+25q)=(1/5)1190}}}

{{{n+5q=238}}}



The system to solve should take the form, {{{system(n+5q=238,n+q=62)}}}.