Question 1039967
{{{(3)/((x+1)^2)=-2}}}


You need to accept  {{{i^2=-1}}}, for the imaginary unit, i.


{{{3/(x+1)^2=-2}}}

{{{(3/(x+1)^2)(x+1)^2=-2(x+1)^2}}}

{{{3=-2(x+1)^2}}}

{{{(x+1)^2=-(3/2)}}}

{{{x+1=0+- sqrt(-3/2)}}}

{{{x=-1+- sqrt(-3/2)}}}

{{{highlight(x=-1+- i*sqrt(3/2))}}}


You can rationalize the denominator if you want.
{{{x=-1+- i*sqrt(3)(sqrt(2))/2}}}

{{{highlight(x=-1+- i(1/2)sqrt(6))}}}