Question 1039959
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The sum of the interior angles of any n-sided polygon is given by *[tex \Large (n\ -\ 2)*180]


For the time being, I'm going to call that number *[tex \Large S], and I leave it to you to calculate the value of *[tex \Large S].


If the angles are proportional, then all of the angles must have a common factor in their measures.  We'll call that common factor *[tex \Large x].  So the first angle is *[tex \Large 2x], the second is *[tex \Large 3x], and so on.  That means we can write:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 2x\ +\ 3x\ +\ 5x\ +\ 9x\ +\ 11x\ =\ S]


So once you have figured out the value of S, plug it into the equation and solve for *[tex \Large x].  Then calculate *[tex \Large 2x], *[tex \Large 3x], and so on.  Check your work to make sure that the angles all add up to your value of *[tex \Large S]


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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