Question 1039888
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Let's say we conduct 13 trials. 8 of those trials has the event happen, while the other 5 trials is where the event doesn't happen.


That's exactly what it means when they say "odds in favor are 8:5"


In this case, p = 8 and q = 5


p/(p+q) = 8/(8+5) = 8/13 = 0.615 (use a calculator for the last step)


The probability of the event occurring is <font size=5 color=red>0.615</font>


Subtract this value from 1 to get the probability of the event not occurring. 


1 - 0.615 = 0.385


The probability of the event NOT occurring is <font size=5 color=red>0.385</font> 


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