Question 1039858
Y=(6-x)/(3+4x)
Y(4+4x)=6-x
X(4y+1)=6-36
X=6-3y/(4y+1)
Replacing x with y
Y=6-3x/(4x-1) which is the inverse

Domain of f, can be any number R except x= -3/4
Since the denominator of f can't be zero
3+4x can't be zero

Similarly the denominator of inverse function can't be zero
Therefore for invers x can't be 1/4
If x= 3  f would be 1/5

What is inverse if we replace x in inverse with 1/5

6-3(1/5) divided by 4(1/5)-1