Question 1039874
{{{ A = A[0]*e^( -.00866x ) }}}
{{{ A[0] = 600 }}} pounds
{{{ x = 120 }}} years
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{{{ A = 600*e^( -.00866*120 ) }}}
{{{ A = 600*e^( -1.0392 ) }}}
{{{ A = 600*.35374 }}}
{{{ A = 212.2425 }}}
After 120 years, there will be 212.2425 pounds left
( calculations on my old TI-35 calculator )