Question 1039852
Begin by squaring both sides,
{{{15-2x=(6-x)^2}}}
{{{15-2x=36-12x+x^2}}}
{{{x^2-10x+21=0}}}
{{{(x-3)(x-7)=0}}}
Two possible solutions:
{{{x-3=0}}}
{{{x=3}}}
and
{{{x-7=0}}}
{{{x=7}}}
Verify the solutions with the original equations to verify they are actual solutions.
Don't skip this step.