Question 1039773
The 10 terms have coefficients of 10C1, 10C2...10C10
each term has the coefficient multiplied by (3x) raised to the 10,9,8,7,... and (2y) raised to the 0,1,2,3,4,...
The total of the exponents will equal 10.  Remember to raise the 3 and the 2 as well.
(3x+2y)^10=
10C0(3x)^10*2y^0=3^10*x^10+10*3^9x^9(2y)+45(10C3)*3^8x^8*4y^2(2y)^2+120*3^7x^7(8y^3)+
210*(3^6)(x^6)(16y^4)+252(3^5)x^5(32y^5)+210(81x^4)(64y^6)+120(27x^3)(128y^7)+45(9x^2)(256y^8)+
10(3x)(512y^9)+1024y^10

10Cn((x term)^n*(y term)^(10-n)