Question 1039712
i don't think so.
the smallest amount she can put in each pocket adds up to 45.
this assumes that one of the pockets is left empty.
0 + 1 + 2 + 3 + 4 + 5 + 6 + 7 + 8 + 9 + 10 = 45.
she couldn't leave 2 pockets empty because then there would not be a different number of dollars in each pocket.
with only 44 dollars, two of the pockets would have to have the same amount.
just subtract 1 from any of the pockets except the one that has 0, and you get a total of 44 with two of the pockets having the same amount.
for example: 10 - 9 = 9 but there is already a pocket with 9.
5 - 1 = 4 but there is already a pocket with 4.
etc.....