Question 1039616
Multiply both sides by  {{{(2x+2)(3x-2)}}}, the simplest or lowest common denominator.  This gives   {{{(x+2)(3x-2)=(3x+2)(2x+2)}}}


{{{3x^2+6x-2x-4=6x^2+2x+6x+4}}}


{{{4x-4=3x^2+8x+4}}}


{{{0=3x^2+4x+8}}}, but the discriminant is  {{{4^2-4*3*8=-80}}}, a negative numbers.  NO REAL SOLUTIONS.  Do you want Complex solutions?


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Now done in your duplicate post.  See there.
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