Question 1039518
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a^2 +b^2 +2b +4a +5=0, then the value of 
{{{(a-b)/(a+b)}}} is _____.  Explain clearly

a) 3
b) -3
c)1/3
d)-1/3
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If {{{a^2 +b^2 +2b +4a +5}}} = {{{0}}}, then (complete the squares (!) )

{{{(a+2)^2 + (b+1)^2}}} = {{{0}}},

which implies a = -2, b = -1  (if the sum of two squares of real numbers is zero, then both addends are zeros).

Having this, calculate the rest.
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