Question 1039582
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First, use the Two-Point Form of an equation of a line:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ y\ -\ y_1\ =\ \left(\frac{y_1\ -\ y_2}{x_1\ -\ x_2}\right)(x\ -\ x_1) ]


where *[tex \Large \left(x_1,y_1\right)] and *[tex \Large \left(x_2,y_2\right)] are the coordinates of the given points.


Then rearrange the results into Standard Form:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ Ax\ +\ By\ =\ C]


using the standard algebraic manipulations of adding equal values to both sides of the equation and multiply both sides of the equation by equal values.  Some authors require A, B, and C to be integers with *[tex \Large A\ \geq\ 0] for proper Standard Form, and this is the case here.


John
*[tex \LARGE e^{i\pi}\ +\ 1\ =\ 0]
My calculator said it, I believe it, that settles it
<img src="http://c0rk.blogs.com/gr0undzer0/darwin-fish.jpg">
*[tex \Large \ \
*[tex \LARGE \ \ \ \ \ \ \ \ \ \  

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