Question 90111
x+2 over x divided by x-2 over 3x. 
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[(x+2)/x] / [(x-2)/3x]

Invert the denomiator and multiply to get:

= [(x+2)/x] * [3x/(x-2)]
Cancel any factor common to numerator and denominator:
= [3(x+2)]/[(x-2)]
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Cheers,
Stan H.