Question 1039480
x = number of pennies
y = number of nickels 
z = number of dimes

xp + y(5p) + z(10p) = 1114 we know that 11.14 is equal to 1114 pennies. Here we have written everything in terms of pennies
y+z = x according to the problem
x+y+z = 248 according to the problem. We can replace y+z here with x 

x+x = 248 Therefore 2x = 248 this gives us x=124 which means we have 124 pennies. Now we have to find the number of dimes and nickels. 

124+ 5y +10z = 1114

Simplifying this problem we have 
5y +10z = 990 and we already know y+z = 124 = x

Now we have two equations and two unknowns

5y +10z = 990 and y+z = 124 If y+z = 124 then y = 124 - z. We replace y in the first equation with z

5(124-z) + 10z = 990 and therefore z = 74. If z is 74 y has to be 50 since y = 124-z

To see if this is correct we can calculate 

124 + 5 (50) + 10 (74) if the total number is 1114, then we have solved the problem correctly.