Question 1039482
 The area of a right triangle is 105m^2. The hypotenuse has length square root 421m. What are the lengths of the legs? 
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Equations:
L*W = 105
L^2 + W^2 = 421
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Substitute for "L" and solve for "W":
L = 105/W
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(105/W)^2 + W^2 = 421
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105 + W^4 = 421 W^2
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W^4 - 421W^2 + 105 = 0
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Ans: Width = 20.51
Length = 421/20.51 = 20.53
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Cheers,
Stan H.
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